y(2x^2-3z^2)=0

Solution for y(2x^2-3z^2)=0 equation:

Simplifying
y(2x2 + -3z2) = 0
(2x2 * y + -3z2 * y) = 0
(2x2y + -3yz2) = 0

Solving
2x2y + -3yz2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '3yz2' to each side of the equation.
2x2y + -3yz2 + 3yz2 = 0 + 3yz2

Combine like terms: -3yz2 + 3yz2 = 0
2x2y + 0 = 0 + 3yz2
2x2y = 0 + 3yz2
Remove the zero:
2x2y = 3yz2

Divide each side by '2y'.
x2 = 1.5z2

Simplifying
x2 = 1.5z2

Take the square root of each side:
x = {-1.224744871z, 1.224744871z}